1/ 背景簡述?/
(1)?根據(jù)?SLVA477B Basic Calculation of a Buck Converter's Power Stage?/ 5 Output Voltage Setting小節(jié)中的如下描述:
Almost all converters set the output voltage with a resistive divider network (which is integrated if they are fixed output voltage converters). With the given feedback voltage, VFB, and feedback bias current, IFB, the voltage divider can be calculated. The current through the resistive divider needs to be at least 100 times as big as the feedback bias current:
幾乎所有轉(zhuǎn)換器都使用電阻分壓器網(wǎng)絡(luò)設(shè)置輸出電壓(如果是固定輸出電壓轉(zhuǎn)換器,則集成該網(wǎng)絡(luò))。使用給定的反饋電壓VFB和反饋偏置電流IFB,可以計算分壓器。通過電阻分壓器的電流需要至少是反饋偏置電流的100倍:
This adds less than 1% inaccuracy to the voltage measurement and for the calculation of the feedback divider, the current into the feedback pin can be neglected. The current also can be a lot higher. The only disadvantage of smaller resistor values is a higher power loss in the resistive divider, but the accuracy is increased a little. With the preceding assumption, the resistors are calculated as follows:
這給電壓測量增加了不到 1% 的誤差,對于反饋分壓器的計算,進(jìn)入反饋引腳的電流可以忽略不計(也就是在I(R1R2) ≥ 100 * I(FB)的情況下,I(FB) 相對 I(R1R2) 是可以忽略的)。電流也可以高得多。電阻值較小的唯一缺點是電阻分壓器中的功率損耗較高,但精度略有提高。根據(jù)上述假設(shè),電阻的計算公式如下:
總結(jié)來說,基于上述公式(9)的方法,需要先使用公式(10)計算取值低邊反饋電阻R2,再通過公式(11)計算取值高邊反饋電阻R1。
(2)?根據(jù)?MPS電源小課堂第三季第十話:DC-DC變換器FB分壓電阻設(shè)計( https://mp.weixin.qq.com/s/QB3rN7M4ydPl6JWyROGHaw ),總結(jié)到“因此,對于不同輸出電壓場景(1V / 1.2V / 1.8V / 2.5V / 3.3V / 5V),建議固定上分壓電阻R1阻值,更改下分壓電阻R2阻值,來獲得近似的環(huán)路特性”。
所以,問題是:
① 在BUCK電路高邊反饋電阻R1和低邊反饋電阻R2的阻值中,是先確定R1,再計算R2?還是反過來?
② TI方法和MPS方法的本質(zhì)區(qū)別在哪里?