基于51單片機(jī)的電子密碼鎖設(shè)計(jì)

要求：

設(shè)計(jì)一個(gè)電子密碼鎖

1. 輸入密碼即可開鎖，可刪除信息，可通過輸入123456789ABCDEF等字符
2. 密碼錯(cuò)誤發(fā)出警報(bào)
3. 用LCD1602顯示相關(guān)信息

當(dāng)輸入正確時(shí) D2會(huì)亮燈，表示輸入正確

密碼輸入錯(cuò)誤時(shí)蜂鳴器會(huì)發(fā)出警報(bào)

部分程序：

#include <reg52.h>

typedef unsigned char u8;

typedef unsigned int u16;

//sbit 特殊功能位聲明：聲明某特殊功能寄存器中的一位

#define key P1????????????????? ?? //按鍵io口

sbit fen=P3^0;????????????????? ?? //蜂鳴器io口

sbit rs=P3^1;??????? //LCD控制口

sbit rw=P3^2;

sbit e=P3^3;

sbit led=P3^4;?????? //LED燈io口

//bit 位變量聲明：定義一個(gè)位變量的值

u8 keyz=17,j=0,biao1=0,a=10,b=10,c=10,d=10;

bit biao=0;

u16 zh;

u8 shu[]={0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,

0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f};

u8 zi[]={"lnput password:"};

u8 num[]={"0123456789ABCDEF"};

void delay(u16 i){

while(i--);

}

/*蜂鳴器*/

void Fen(u8 a,b)?? //蜂鳴器發(fā)聲函數(shù)

{

u8 i,j;

for(i=0;i<a;i++)

{

for(j=0;j<100;j++)

{fen=~fen;delay(b);}

}

}

/*LCD*/

void writecom(u8 com){????????????????? //LCD寫指令

rs=0;

rw=0;

e=0;

P0=com;

delay(5);

e=1;

e=0;

}

void writedat(u8 dat){???????????? //LCD寫數(shù)據(jù)

rs=1;

rw=0;

e=0;

P0=dat;

delay(5);

e=1;

e=0;

}

void initlcd(){??????????????????? ?? //LCD初始化函數(shù)

writecom(0x38);?? //顯示模式設(shè)置

writecom(0x0c);

writecom(0x06);

}

void xian(){????? //LCD顯示數(shù)字函數(shù)

writedat(num[keyz]);

if(a==10){a=keyz; }????????????? ?? //對(duì)abcd，四位數(shù)的單獨(dú)賦值

else if(b==10){b=keyz;}

else if(c==10){c=keyz;}

else{d=keyz;}

if(j!=3){j++;}biao=0;

}

/*鍵盤*/

void Key(){u8 a=0;??????????????????? //矩形式鍵盤函數(shù)

if(key!=0x0f){delay(1000);

if(key!=0x0f){

key=0x0f;

switch(key){

case 0x07: keyz=0;biao=1;break;

case 0x0b: keyz=1;biao=1;break;

case 0x0d: keyz=2;biao=1;break;

case 0x0e: keyz=3;biao=1;break;

}

key=0xf0;

switch(key){

case 0x70: keyz=keyz;biao=1;break;

case 0xb0: keyz=keyz+4;biao=1;break;

case 0xd0: keyz=keyz+8;biao=1;break;

case 0xe0: keyz=keyz+12;biao=1;break;

}

}

while((a<50)&&(key!=0xf0)){a++;delay(10000);}

}

}

void shi(){u8 i; ? // 按鍵值判斷函數(shù)

if(biao&&keyz!=15){? //判斷標(biāo)志位biao是否為1，為1則有按鍵操作并且按鍵的值不等于15

writecom(0x80+0x40+j);??????????????????????? ? //數(shù)字顯示位置進(jìn)行累加操作

if(j<0){j=0;}?????????????????????????????????????? ? //數(shù)字顯示位置邊界

switch(keyz){?????????????????????????????????????????????????? ? //switch判斷按鍵并執(zhí)行對(duì)應(yīng)操作

case 0:xian(); break;

case 1:xian(); break;

case 2:xian(); break;

case 3:xian(); break;

case 4:xian(); break;

case 5:xian(); break;

case 6:xian(); break;

case 7:xian(); break;

case 8:xian(); break;

case 9:xian(); break;

case 10:writedat(num[keyz]);

j++;biao=0;break;

case 11:writedat(num[keyz]);

j++;biao=0;break;

case 12:

biao1=0;???????????????????????????????????????????? ? //重置標(biāo)志位biao1,上鎖

biao=0;break;

case 13:writecom(0x01);??????? delay(1000);??? ? //全屏清除

for(i=0;i<sizeof(zi);i++){

writecom(0x80+i);

writedat(zi[i]);???????????????? }

j=0;biao=0;break;

case 14: ????????????????????????????????????????????????????????????????????? ??//對(duì)當(dāng)前數(shù)字位刪除的操作

writedat(' ');

j--;

writecom(0x80+0x40+j);writedat(' ');

biao=0;break;

case 15:??????????????????? ? //確定按鍵

j++;biao=0;break;

}

}

if(keyz==15){?? ?????????????????????????????????????????????????????????? ?//判斷按鍵值如果等于15，便視為按下確定鍵

writecom(0x01);delay(1000);

zh=a*1000+b*100+c*10+d;??????????????????????????????????????????? //將ABCD，四位數(shù)合并并進(jìn)行判斷是否為正確密碼

if(zh==1234){? //設(shè)密碼為1234

j=0;

biao1=1;?????????????????????????????????????????????????????????????????????? //將biao1標(biāo)志位置1便為密碼正確

keyz=17;?????????????????? ? ??????????????????????????????????????????????? ?//使按鍵值跳出最大值15便不會(huì)循壞顯示

}

else{

j=0;

biao1=0;???????????????????????????????????????????????????????????????????????????????????? //反之密碼錯(cuò)誤

keyz=17;

Fen(20,200); ?????????????????? ???????????//蜂鳴器報(bào)警

}

zh=0;a=10,b=10,c=10,d=10;???????????????????????????????????? //重置ABCD變量

for(i=0;i<sizeof(zi);i++){

writecom(0x80+i);

writedat(zi[i]);????????????????????? ?? }

}

}

內(nèi)容包括：

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